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A particle starts from the origin at t = 0 with an initial velocity of 3.0 î m/s and moves in the x-y plane with a constant acceleration (6.0 î + 4.0 ĵ) m/s². The x-coordinate of the particle at the instant when its y-coordinate is 32 m is D metres. The value of D is

1. 50
2. 60
3. 40
4. 32

Correct answer: 60

Solution

From y = (1/2)(4)t^2 = 2t^2 = 32, t = 4 s. Then x = 3t + (1/2)(6)t^2 = 12 + 48 = 60 m.

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