StreakPeaked· Practice

ExamsJEE MainPhysics

A uniform sphere of mass 500 g rolls without slipping on a plane horizontal surface with its centre moving at a speed of 5.00 cm/s. Its kinetic energy is:

  1. 1.13 × 10⁻³ J
  2. 8.75 × 10⁻³ J
  3. 6.25 × 10⁻⁴ J
  4. 8.75 × 10⁻⁴ J

Correct answer: 8.75 × 10⁻⁴ J

Solution

For a solid sphere rolling without slipping, KE = (1/2)mv^2 + (1/2)Iw^2 = (7/10)mv^2. With m=0.5 kg and v=0.05 m/s, KE = 0.7*0.5*0.0025 = 8.75e-4 J.

Related JEE Main Physics questions

⚔️ Practice JEE Main Physics free + battle 1v1 →