Particle A of mass m1 moving with velocity (√3 i + j) m s⁻¹ collides with another particle B of mass m2 which is at rest initially. Let V1 and V2 be the velocities of particles A and B after collision respectively. If m1 = 2m2 and after collision V1 = (i + √3 j) m s⁻¹, the angle between V1

Question

Particle A of mass m1 moving with velocity (√3 i + j) m s⁻¹ collides with another particle B of mass m2 which is at rest initially. Let V1 and V2 be the velocities of particles A and B after collision respectively. If m1 = 2m2 and after collision V1 = (i + √3 j) m s⁻¹, the angle between V1 and V2 is:

Accepted Answer

105°. The angle between the velocities V1 and V2 can be determined using the conservation of momentum and the relationship between the masses. Given that m1 is twice m2 and the final velocity of A is at a specific angle, the resulting velocity of B must be oriented such that the angle between them is 105°, ensuring momentum is conserved in both the x and y directions.

Solution

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