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The difference between the radii of 3rd and 4th orbits of Li2+ is ΔR1. The difference between the radii of 3rd and 4th orbits of He+ is ΔR2. ΔR1: ΔR2 is:
- 8: 3
- 2: 2
- 3: 8
- 2: 3
Correct answer: 2: 3
Solution
Radius r = 0.529 n^2/Z. ΔR(3->4) = (16-9)/Z = 7/Z. For Li2+ (Z=3): ΔR1 = 7/3; for He+ (Z=2): ΔR2 = 7/2. ΔR1:ΔR2 = (7/3):(7/2) = 2:3.
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