Exams › JEE Main › Physics
A body is moving in a low circular orbit about a planet of mass M and radius R. The radius of the orbit can be taken to be R itself. Then the ratio of the speed of this body in the orbit to the escape velocity from the planet is
- √2
- 1/√2
- 2
- 1
Correct answer: 1/√2
Solution
Orbital speed v_o = sqrt(GM/R) and escape speed v_e = sqrt(2GM/R), so v_o/v_e = 1/sqrt(2).
Related JEE Main Physics questions
⚔️ Practice JEE Main Physics free + battle 1v1 →