Exams › JEE Main › Physics
Dimensional formula for thermal conductivity is (here K denotes the temperature)
- MLT²K
- ML⁻³K
- MLT⁻³K⁻¹
- MLT⁻²K⁻²
Correct answer: MLT⁻³K⁻¹
Solution
From Q = k A (dT) t / d, k = Q d/(A dT t) = (ML^2T^-2 * L)/(L^2 * K * T) = M L T^-3 K^-1.
Related JEE Main Physics questions
⚔️ Practice JEE Main Physics free + battle 1v1 →