StreakPeaked· Practice

ExamsJEE MainPhysics

Dimensional formula for thermal conductivity is (here K denotes the temperature)

  1. MLT²K
  2. ML⁻³K
  3. MLT⁻³K⁻¹
  4. MLT⁻²K⁻²

Correct answer: MLT⁻³K⁻¹

Solution

From Q = k A (dT) t / d, k = Q d/(A dT t) = (ML^2T^-2 * L)/(L^2 * K * T) = M L T^-3 K^-1.

Related JEE Main Physics questions

⚔️ Practice JEE Main Physics free + battle 1v1 →