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ExamsJEE MainPhysics

Equation of travelling wave on a stretched string of linear density 5 g/m is y = 0.03 sin(450 t - 9x) where distance and time are measured in SI units. The tension in the string is:

  1. 1 N
  2. 7.5 N
  3. 5 N
  4. 12.5 N

Correct answer: 12.5 N

Solution

The tension in the string can be calculated using the wave speed and linear density. The wave speed is derived from the angular frequency and wave number in the equation, leading to a tension of 12.5 N when applying the formula T = μv², where μ is the linear density.

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