A particle of mass m is moving along a trajectory given by
x = x0 + a cos ωt

y = y0 + b sin ωt
The torque, acting on the particle about the origin, at t = 0 is:

Question

A particle of mass m is moving along a trajectory given by
x = x0 + a cos ωt

y = y0 + b sin ωt
The torque, acting on the particle about the origin, at t = 0 is:

Accepted Answer

m y0 aω2 k. At t = 0, the particle's position is (x0, y0), and the torque is calculated using the formula τ = r × F, where r is the position vector and F is the force. The force acting on the particle is its mass times acceleration, which is derived from the second derivatives of the position equations, leading to the correct torque expression of m y0 aω² k.

A particle of mass m is moving along a trajectory given by x = x0 + a cos ωt y = y0 + b sin ωt The torque, acting on the particle about the origin, at t = 0 is:

Solution

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