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A mass of 10 kg is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point, the rope deviated at an angle of 45° at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is (g = 10 m s⁻²)

1. 100 N
2. 70 N
3. 140 N
4. 200 N

Correct answer: 100 N

Solution

Equilibrium of the mass-point on the rope: T cos45 = mg and T sin45 = F. Dividing gives F = mg = 10*10 = 100 N.

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