Two forces P and Q, of magnitude 2F and 3F, respectively, are at an angle θ with each other. If the force Q is doubled, then their resultant also gets doubled. Then, the angle θ is -

Question

Accepted Answer

120°. R^2 = 13F^2 + 12F^2 cos(theta). Doubling Q to 6F: R'^2 = 40F^2 + 24F^2 cos(theta). Requiring R' = 2R gives 40 + 24cos = 52 + 48cos, so cos(theta) = -1/2 and theta = 120 deg.

Two forces P and Q, of magnitude 2F and 3F, respectively, are at an angle θ with each other. If the force Q is doubled, then their resultant also gets doubled. Then, the angle θ is -

Solution

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