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The magnitude of torque on a particle of mass 1 kg is 2.5 N m about the origin. If the force acting on it is 1 N, and the distance of the particle from the origin is 5m, the angle between the force and the position vector is (in radians):

1. π/8
2. π/6
3. π/4
4. π/3

Correct answer: π/6

Solution

The torque is given by the formula τ = r × F × sin(θ), where τ is the torque, r is the distance from the origin, F is the force, and θ is the angle between the force and the position vector. Rearranging the formula and substituting the known values, we find that the angle θ that satisfies the equation for the given torque and force is π/6 radians.

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