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A particle moves from the point (2.0i + 4.0j) m. at t = 0, with an initial velocity (5.0i + 4.0j) m s⁻¹. It is acted upon by a constant force which produces a constant acceleration (4.0i + 4.0j) ms⁻². What is the distance of the particle from the origin at time 2 s?

1. 15 m
2. 20√2 m
3. 10√2 m
4. 5 m

Correct answer: 20√2 m

Solution

The correct option is right because, using the kinematic equations, the position of the particle after 2 seconds can be calculated by adding the initial position to the displacement caused by the initial velocity and the acceleration. This results in a final position that, when calculated, gives a distance of 20√2 m from the origin.

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