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A monochromatic beam of light has a frequency ν = 3/(2π) × 10¹² Hz and is propagating along the direction (î + ĵ)/√2. It is polarized along the k̂ direction. The acceptable form for the magnetic field is:
- (E0/C) ((î − ĵ)/√2) cos[10⁴ ((î − ĵ)/√2)·r − (3×10¹²)t]
- (E0/C) ((î − ĵ)/√2) cos[10⁴ ((î + ĵ)/√2)·r − (3×10¹²)t]
- (E0/C) k̂ cos[10⁴ ((î + ĵ)/√2)·r + (3×10¹²)t]
- (E0/C) ((î + ĵ + k̂)/√3) cos[10⁴ ((î + ĵ)/√2)·r + (3×10¹²)t]
Correct answer: (E0/C) ((î − ĵ)/√2) cos[10⁴ ((î + ĵ)/√2)·r − (3×10¹²)t]
Solution
The wave propagates along n = (i+j)/sqrt2 with E along k. B = (1/c)(n x E), giving B along (i-j)/sqrt2 with magnitude E0/c. The phase must contain the propagation direction (i+j)/sqrt2 as k.r and the form k.r - omega*t with omega = 2*pi*nu = 3x10^12. Only the option with B along (i-j)/sqrt2 and phase 10^4((i+j)/sqrt2).r - (3x10^12)t is fully consistent.
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