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ExamsJEE MainPhysics

The end correction of a resonance column is 1 cm. If the shortest length resonating with the tuning fork is 10cm, the next resonating length should be -

  1. 32 cm
  2. 40 cm
  3. 28 cm
  4. 36 cm

Correct answer: 32 cm

Solution

With end correction e=1 cm, first resonance gives lambda/4 = L1+e = 10+1 = 11 cm, so lambda = 44 cm. Next resonance: 3*lambda/4 = L2+e = 33 cm -> L2 = 32 cm.

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