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In a common emitter amplifier circuit using an n-p-n transistor, the phase difference between the input and the output voltages will be -
- 45°
- 90°
- 135°
- 180°
Correct answer: 180°
Solution
In a common emitter amplifier, the output voltage is inverted relative to the input voltage, resulting in a phase difference of 180 degrees. This means that when the input signal goes positive, the output signal goes negative, confirming the phase inversion characteristic of this configuration.
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