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ExamsJEE MainPhysics

A particle is acted upon by constant forces 4î + ĵ - 3k̂ and 3î + ĵ - k̂ which displace it from a point î + 2ĵ + 3k̂ to the point 5î + 4ĵ + k̂. The work done in standard units by the forces is given by

  1. 15
  2. 30
  3. 25
  4. 40

Correct answer: 40

Solution

Total force = 7i+2j-4k, displacement = 4i+2j-2k. Work = 28+4+8 = 40.

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