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A particle is acted upon by constant forces 4î + ĵ - 3k̂ and 3î + ĵ - k̂ which displace it from a point î + 2ĵ + 3k̂ to the point 5î + 4ĵ + k̂. The work done in standard units by the forces is given by
- 15
- 30
- 25
- 40
Correct answer: 40
Solution
Total force = 7i+2j-4k, displacement = 4i+2j-2k. Work = 28+4+8 = 40.
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