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The upper 3/4 th portion of a vertical pole subtends an angle tan⁻¹(3/5) at a point in the horizontal plane through its foot and at a distance 40 m from the foot. A possible height of the vertical pole is
- 80 m
- 20 m
- 40 m
- 60 m
Correct answer: 40 m
Solution
The height of the pole can be determined using the tangent of the angle subtended, which relates the height of the pole to the distance from the foot. Given that the angle is tan⁻¹(3/5), we can set up the relationship using the tangent function, leading to a height of 40 m for the upper 3/4 portion of the pole.
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