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If the magnetic field in a plane electromagnetic wave is given by B = 3×10⁻⁸sin(1.6×10³ x + 48×10¹⁰ t) ĵ T, then what will be expression for electric field?

1. E = (60sin(1.6×10³ x + 48×10¹⁰ t)) V/m
2. E = (9sin(1.6×10³ x + 48×10¹⁰ t)) V/m
3. E = (3×10⁻⁸sin(1.6×10³ x + 48×10¹⁰ t)) V/m
4. E = (3×10⁻⁸sin(1.6×10³ x + 48×10¹⁰ t)) V/m

Correct answer: E = (9sin(1.6×10³ x + 48×10¹⁰ t)) V/m

Solution

E0 = c*B0 = (3e8)*(3e-8) = 9 V/m, with the same phase argument as B. So E = 9*sin(1.6e3 x + 48e10 t) V/m.

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