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Two resistors have equal resistance at 0°C, and their temperature coefficients of resistance are α1 and α2. The temperature coefficients of resistance for their combination in series and in parallel are approximately

1. (α1 + α2)/2, α1 + α2
2. α1 + α2, (α1 + α2)/2
3. α1 + α2, α1α2/(α1 + α2)
4. (α1 + α2)/2, (α1 + α2)/2

Correct answer: (α1 + α2)/2, (α1 + α2)/2

Solution

The temperature coefficient of resistance for resistors in series and parallel can be averaged when the resistors have equal resistance, leading to the same value for both configurations. Thus, the coefficients for both combinations are approximately (α1 + α2)/2.

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