Exams › JEE Main › Physics
A copper sphere of mass 100 g is initially at temperature T. It is placed into a copper calorimeter of mass 100 g containing 170 g of water initially at room temperature. After thermal equilibrium is reached, the final temperature of the whole system is 75°C. Find T. [Given: room temperature = 30°C, specific heat of copper = 0.1 cal/g°C]
- 1250°C
- 825°C
- 800°C
- 885°C
Correct answer: 885°C
Solution
Heat lost by copper sphere = heat gained by water and calorimeter: 100*0.1*(T-75) = 170*1*(75-30) + 100*0.1*(75-30). So 10*(T-75) = 7650 + 450 = 8100, giving T - 75 = 810, T = 885 C.
Related JEE Main Physics questions
⚔️ Practice JEE Main Physics free + battle 1v1 →