Exams › JEE Main › Physics
A body of mass 2 kg makes an elastic collision with a second body at rest and continues to move in the original direction but with one fourth of its original speed. What is the mass of the second body?
- 1.0 kg
- 1.5 kg
- 1.8 kg
- 1.2 kg
Correct answer: 1.2 kg
Solution
For an elastic collision with a stationary target, v1' = (m1-m2)/(m1+m2)*v = v/4. So (2-m2)/(2+m2)=1/4 -> 8-4 m2 = 2 + m2 -> m2 = 1.2 kg.
Related JEE Main Physics questions
⚔️ Practice JEE Main Physics free + battle 1v1 →