In a collinear collision, a particle with an initial speed v0 strikes a stationary particle of the same mass. If the final total kinetic energy is 50% greater than the original kinetic energy, the magnitude of the relative velocity between the two particles, after collision, is:

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Accepted Answer

√2 v0. Momentum: v1 + v2 = v0. KE up 50%: v1^2 + v2^2 = 1.5 v0^2. Then (v1 - v2)^2 = 2(v1^2 + v2^2) - (v1 + v2)^2 = 3 v0^2 - v0^2 = 2 v0^2, so |v1 - v2| = sqrt(2) v0.

In a collinear collision, a particle with an initial speed v0 strikes a stationary particle of the same mass. If the final total kinetic energy is 50% greater than the original kinetic energy, the magnitude of the relative velocity between the two particles, after collision, is:

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