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ExamsJEE MainPhysics

A person trying to lose weight by burning fat lifts a mass of 10 kg up to a height of 1 m 1000 times. Assume that the potential energy lost each time he lowers the mass is dissipated. How much fat will he use up considering the work done only when the weight is lifted up? Fat supplies 3.8 × 10⁷ J of energy per kg which is converted to mechanical energy with a 20% efficiency rate. Take g = 9.8 m s⁻².

  1. 9.89 × 10⁻³ kg
  2. 12.89 × 10⁻³ kg
  3. 2.45 × 10⁻³ kg
  4. 46 × 10⁻⁴ kg

Correct answer: 12.89 × 10⁻³ kg

Solution

The correct option is right because the total work done in lifting the mass is calculated using the formula for gravitational potential energy, which is then adjusted for the efficiency of energy conversion from fat. After determining the total energy required and considering the efficiency, the amount of fat needed to provide that energy is accurately calculated, resulting in 12.89 × 10⁻³ kg.

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