Exams › JEE Main › Physics

A block of mass M is dragged over a smooth horizontal surface by a rope of mass m. When a force P is applied at the free end of the rope, the force transmitted by the rope to the block is:

1. Pm/(M + m)
2. Pm/(M - m)
3. P
4. PM/(M + m)

Correct answer: PM/(M + m)

Solution

The force transmitted by the rope to the block is determined by the system's total mass and the applied force. Since both the block and the rope are in motion, the effective mass that the applied force P acts upon is the sum of the masses M and m, leading to the formula P multiplied by the mass of the block divided by the total mass.

Related JEE Main Physics questions

• Which of the following has the same SI unit as impulse?
• A monkey slides downward from a tree branch with uniform acceleration. If the maximum tension the branch can withstand is 75% of the monkey’s weight, what is the least downward acceleration that will allow the monkey to descend without snapping the branch?
• A 1000 kg car is travelling at 30 m/s. The brakes are applied until it stops. If the friction force between the tyres and the road is 5000 N, how long will the car take to come to rest?
• A rocket initially ejects gas from its rear at a mass rate of 0.1 kg s⁻¹. If the exhaust speed relative to the rocket is 50 m s⁻¹ and the rocket’s mass is 2 kg, what is its acceleration in m s⁻²?
• A block of mass M rests on a rough level floor with coefficient of friction μ. A person applies a horizontal pull, but the block remains at rest. If the total contact force exerted by the floor on the block is F, then
• Which of the following types of motion on a frictionless plane surface occurs without any force acting on the body?

⚔️ Practice JEE Main Physics free + battle 1v1 →