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A projectile is given an initial velocity of (î + 2ĵ) m/s, where î is along the ground and ĵ is along the vertical. If g = 10 m/s², the equation of trajectory is:

1. y = x - 5x²
2. y = 2x - 5x²
3. 4y = 2x - 5x²
4. 4y = 2x - 25x²

Correct answer: y = 2x - 5x²

Solution

Here ux = 1, uy = 2, so tan(theta) = 2 and the trajectory is y = 2x - (g/(2 ux^2)) x^2 = 2x - (10/2) x^2 = 2x - 5x^2.

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