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A boy playing on the roof of a 10 m high building throws a ball with a speed of 10 m/s at an angle of 30° with the horizontal. How far from the throwing point will the ball be at the height of 10 m from ground? [g = 10 m/s², sin 30° = 1/2, cos 30° = √3/2]

1. 5.20 m
2. 4.33 m
3. 2.60 m
4. 8.66 m

Correct answer: 8.66 m

Solution

The correct option is right because the horizontal distance traveled by the ball can be calculated using the horizontal component of the initial velocity and the time it takes to reach the height of 10 m. By applying the kinematic equations for projectile motion, we find that the ball lands 8.66 m away from the throwing point.

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