In a common-emitter transistor amplifier, if the load impedance is 1 kΩ, h_fe = 50, and h_oe = 25, what is the current gain?

-24.8
-15.7
-5.2
-48.78

Correct answer: -48.78

Solution

The current gain in a common-emitter amplifier can be calculated using the formula that incorporates the load impedance and the transistor parameters. Given the values, the calculation yields a current gain of approximately -48.78, indicating a significant amplification of the input current with a phase inversion.

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