StreakPeaked· Practice

ExamsJEE MainPhysics

If M(A, Z), Mₚ and Mₙ represent, respectively, the mass of the nucleus ^(A)_(Z)X, the proton mass and the neutron mass, all expressed in atomic mass units (1 u = 931.5 MeV/c²), and BE denotes the binding energy in MeV, which relation is correct?

  1. M(A, Z) = ZMₚ + (A - Z)Mₙ - BE/c²
  2. M(A, Z) = ZMₚ + (A - Z)Mₙ + BE
  3. M(A, Z) = ZMₚ + (A - Z)Mₙ - BE
  4. M(A, Z) = ZMₚ + (A - Z)Mₙ + BE/c²

Correct answer: M(A, Z) = ZMₚ + (A - Z)Mₙ - BE/c²

Solution

Binding energy is released when nucleons bind, so the nuclear mass is less than the sum of constituent masses by BE/c^2: M(A,Z) = ZMp + (A-Z)Mn - BE/c^2.

Related JEE Main Physics questions

⚔️ Practice JEE Main Physics free + battle 1v1 →