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An AC generator rated at 220 V has an internal resistance of 10 Ω and is connected to an external resistance of 100 Ω. What power is dissipated in the external circuit?

1. 484 W
2. 400 W
3. 441 W
4. 369 W

Correct answer: 400 W

Solution

Total resistance = 10 + 100 = 110 ohm, so I = 220/110 = 2 A. Power in external resistor = I^2 * 100 = 4 * 100 = 400 W.

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