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ExamsJEE MainPhysics

A coil having a resistance of 50 Ω is joined to a 5.0 V battery. After 0.1 s from the moment of connection, the current through the coil becomes 60 mA. What is the inductance of the coil?

  1. 5.5 H
  2. 1.5 H
  3. 2.5 H
  4. 9.5 H

Correct answer: 5.5 H

Solution

Final current I0 = V/R = 5/50 = 0.1 A. Using i = I0(1 - e^(-Rt/L)): 0.06 = 0.1(1 - e^(-5/L)) -> e^(-5/L) = 0.4 -> 5/L = ln(2.5) = 0.916 -> L = 5.46 H ~ 5.5 H.

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