In a series L-C circuit, the current reaches its peak when the inductance is 0.5 H and the capacitance is 8 μF. What is the angular frequency of the applied alternating voltage?

5000 rad/sec
4000 rad/sec
2 × 10⁵ rad/sec
500 rad/sec

Correct answer: 500 rad/sec

Solution

At peak current the circuit is at resonance: omega = 1/sqrt(LC) = 1/sqrt(0.5 * 8e-6) = 1/sqrt(4e-6) = 1/(2e-3) = 500 rad/s.

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