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Two liquids having densities d1 and d2 are made to pass through identical capillary tubes under the same pressure difference. If t1 and t2 are the times required for equal masses of the two liquids to flow out, then the ratio of their coefficients of viscosity is
- (d1 t1)/(d2 t2)
- t1/t2
- (d2 t2)/(d1 t1)
- √((d1 t1)/(d2 t2))
Correct answer: (d1 t1)/(d2 t2)
Solution
The correct option is derived from the relationship between viscosity, density, and flow rate in capillary tubes. According to Poiseuille's law, the viscosity of a fluid is directly proportional to the product of its density and the time taken for a given mass to flow, leading to the ratio of viscosities being expressed as (d1 t1)/(d2 t2).
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