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A wire has a diameter of 12 mm and a length of 1 m. Its top end is fixed, and the free end is turned by 30°. What is the angle of shear produced in the wire?

1. 18°
2. 0.18°
3. 36°
4. 0.36°

Correct answer: 0.18°

Solution

For torsion, arc length matching gives shear angle theta = r*phi/L. With r = 6 mm, L = 1000 mm, phi = 30 deg: theta = 6*30/1000 = 0.18 deg.

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