A 4 kg block is suspended from a light spring that follows Hooke’s law, and the spring extends by 2 cm. If an external agent stretches the same spring by 5 cm, the work done is (take g = 9.8 m/s²):

Question

Accepted Answer

2.450 joule. The work done on a spring is calculated using the formula W = 0.5 * k * x², where k is the spring constant and x is the extension. Given that the spring extends by 2 cm under a 4 kg weight, we can find the spring constant and then use it to calculate the work done when the spring is stretched by 5 cm, resulting in 2.450 joules.

A 4 kg block is suspended from a light spring that follows Hooke’s law, and the spring extends by 2 cm. If an external agent stretches the same spring by 5 cm, the work done is (take g = 9.8 m/s²):

Solution

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