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A 1 kg particle starts from rest and is acted upon by a time-varying force F=(2t î+3t² ĵ) N, where î and ĵ are unit vectors along the x- and y-axes. What is the instantaneous power delivered by the force at time t?
- (2t²+3t³) W
- (2t²+4t⁴) W
- (2t³+3t³) W
- (2t³+3t⁵) W
Correct answer: (2t³+3t⁵) W
Solution
The instantaneous power delivered by a force is calculated as the dot product of the force vector and the velocity vector. By first determining the velocity from the force using Newton's second law and then substituting it into the power formula, we find that the correct expression for power at time t is ((2t³+3t⁵) ext{ W}.
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