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A bullet is launched from a gun. The force acting on it is F = 600 − 2 × 10⁵ t, where F is measured in newtons and t in seconds. The force on the bullet drops to zero immediately after it exits the barrel. What is the average impulse given to the bullet?

1. 1.8 Ns
2. zero
3. 9 Ns
4. 0.9 Ns

Correct answer: 0.9 Ns

Solution

The average impulse is calculated by integrating the force over the time the bullet is in the barrel. Given the force function, the impulse can be found by evaluating the area under the force-time graph, which results in 0.9 Ns.

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