Exams › JEE Main › Physics
For a particle of mass m kg moving along a straight line under a force, the displacement x (in m) and time t (in s) are connected by t = √x + 3. The particle’s displacement at the instant when its velocity becomes zero is
- 2 m
- 4 m
- zero
- 6 m
Correct answer: zero
Solution
From t = sqrt(x) + 3, sqrt(x) = t-3 so x = (t-3)^2 and v = dx/dt = 2(t-3). Velocity is zero at t = 3 s, at which x = (3-3)^2 = 0, so the displacement is zero.
Related JEE Main Physics questions
⚔️ Practice JEE Main Physics free + battle 1v1 →