Exams › JEE Main › Maths
Find the domain of each function: (i) y = 1/sqrt(log_(x+1)(x - 1)) (ii) y = sqrt(logₓ(x² - 1)) (iii) y = log_(x-2)((x² - 4)/(x + 1))
- (i) x > 2; (ii) x > sqrt(2); (iii) x in (2,3) U (3, infinity)
- (i) x > 1; (ii) x > 1; (iii) x > 2
- (i) x > 2; (ii) x > 1; (iii) x in (2, infinity)
- (i) no solution; (ii) x > sqrt(2); (iii) x in (3, infinity)
Correct answer: (i) x > 2; (ii) x > sqrt(2); (iii) x in (2,3) U (3, infinity)
Solution
Each part combines base restrictions, argument-positivity, and the sign of the logarithm. Solving the simultaneous conditions yields the listed domains.
Related JEE Main Maths questions
⚔️ Practice JEE Main Maths free + battle 1v1 →