Find the range of f(x) = (x² + x + 2)/(x² + x + 1).
[1, 2]
[1, inf)
[2, 7/3]
(1, 7/3]
Correct answer: (1, 7/3]
Solution
f(x) = 1 + 1/(x² + x + 1). Let g = x² + x + 1 = (x + 1/2)² + 3/4, so g in [3/4, inf). Then 1/g in (0, 4/3]. Hence f = 1 + 1/g in (1, 1 + 4/3] = (1, 7/3]. The value 1 is not attained (would require g -> inf).