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Find all real x satisfying the double inequality 7 - 3x < x - 1 <= 2x + 9.
- x > 2
- -10 <= x < 2
- x in (2, infinity) and x >= -10, i.e. x > 2
- x <= -10
Correct answer: x > 2
Solution
Solve each part separately. The left inequality yields x > 2; the right yields x >= -10. The intersection of x > 2 and x >= -10 is x > 2.
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