StreakPeaked· Practice

ExamsJEE MainMaths

By eliminating the arbitrary constant c, form the differential equation whose general solution is y = c*(1 - x²) + sqrt(1 - x²).

  1. (1 - x²)*dy/dx + 2*x*y = x*sqrt(1 - x²)
  2. (1 - x²)*dy/dx - 2*x*y = x*sqrt(1 - x²)
  3. (1 - x²)*dy/dx + 2*x*y = sqrt(1 - x²)
  4. (1 - x²)*dy/dx + x*y = x*sqrt(1 - x²)

Correct answer: (1 - x²)*dy/dx + 2*x*y = x*sqrt(1 - x²)

Solution

Differentiating y = c*(1 - x²) + sqrt(1 - x²) gives dy/dx in terms of c and x. From the original equation c = (y - sqrt(1 - x²))/(1 - x²). Substituting this c back and clearing denominators removes the constant and yields a first-order linear differential equation whose right side carries the sqrt(1 - x²) coming from the particular part of the solution.

Related JEE Main Maths questions

⚔️ Practice JEE Main Maths free + battle 1v1 →