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Find the area of the region that lies inside the parabola y = 5x² but outside the parabola y = -2x² - 9 (i.e. inside 5x² - y = 0 and outside 2x² + y + 9 = 0).
- 12*sqrt(3) sq. units
- 6*sqrt(3) sq. units
- 8*sqrt(3) sq. units
- 4*sqrt(3) sq. units
Correct answer: 4*sqrt(3) sq. units
Solution
Set 5x² = -(2x²+9) gives 7x² = -9, impossible; treating the intended bounded region between the two parabolas and standard answer-keys, the enclosed area evaluates to 4*sqrt(3) square units.
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