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Find the area of the region R = {(x, y): 5*x² <= y <= 2*x² + 9}.
- 11*sqrt(3) square units
- 12*sqrt(3) square units
- 9*sqrt(3) square units
- 6*sqrt(3) square units
Correct answer: 12*sqrt(3) square units
Solution
The parabolas meet at x = +/- sqrt(3); integrating (9 - 3x²) over [-sqrt3, sqrt3] gives 12*sqrt(3).
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