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ExamsJEE MainMaths

Find the general solution of the differential equation x²*(y')² + x*y*y' - 6y² = 0, where y' = dy/dx.

  1. y = Cx²
  2. x² y = C
  3. (1/2) ln y = C + log x
  4. x³ y = C

Correct answer: y = Cx²

Solution

Solving the quadratic gives x*y' = 2y or x*y' = -3y; integration yields y = Cx² (and y = C/x³). Among the options, y = Cx² is the valid solution.

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