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An ellipse with principal axes along the coordinate axes passes through (-3, 1) and (2, -2). Find the value of 10 times the square of the length of its semi-minor axis.
- 64
- 320/41
- 32
- 16/3
Correct answer: 64
Solution
Solving 9/A + 1/B = 1 and 4/A + 4/B = 1 gives A = 32/3 and B = 32/5; the semi-minor axis squared is the smaller value 32/5, so 10 * (32/5) = 64.
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