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Find the focal length (distance between the foci) of the hyperbola x² - 3y² - 4x - 6y - 11 = 0.
- 4
- 6
- 8
- 10
Correct answer: 8
Solution
Completing the square gives (x-2)²/12 - (y+1)²/4 = 1 with a² = 12, b² = 4, so c = 4 and the focal length 2c = 8.
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