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An ellipse has foci S(5, 12) and S'(-12, 5) and passes through the origin. Find its eccentricity.
- 1/2
- 1/sqrt(3)
- 1/sqrt(2)
- 2/3
Correct answer: 1/sqrt(2)
Solution
From the origin both focal distances are 13, giving 2a = 26; the foci are 2c = 13*sqrt(2) apart, so e = c/a = 1/sqrt(2).
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