StreakPeaked· Practice

ExamsJEE MainMaths

Let x and y be real numbers satisfying x² + 9y² - 4x + 6y + 4 = 0. Find the maximum value of (4x - 9y).

  1. 16
  2. 10
  3. 22
  4. 32

Correct answer: 16

Solution

On the ellipse, 4x - 9y = 11 + 4cos(t) - 3sin(t), whose maximum is 11 + sqrt(16+9) = 16.

Related JEE Main Maths questions

⚔️ Practice JEE Main Maths free + battle 1v1 →