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Find the equation of a common tangent to the curves y² = 16x and xy = -4.
- x + 2y + 8 = 0
- x - 2y + 16 = 0
- 2x - y + 2 = 0
- x - y + 4 = 0
Correct answer: x + 2y + 8 = 0
Solution
Tangent to the parabola is y = mx + 4/m; requiring it to touch xy = -4 gives m = -1/2 and the line x + 2y + 8 = 0.
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