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A hyperbola has conjugate axis of length 5 and the distance between its foci equal to 13. Find its eccentricity.
- 13/12
- 2
- 13/6
- 13/8
Correct answer: 13/12
Solution
With b = 5/2 and ae = 13/2, b² = (ae)² - a² gives a² = 36, a = 6, so e = (ae)/a = (13/2)/6 = 13/12.
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